var arr1:Array = new Array();
arr1.push(item1);
arr1.push(item2);
arr1.push(item3);
then arr1 and its elements get passed to other functions is there a way to know the index of an item in the array?
GetParentArrayIndex(item2) would give me 1;
I have a tricky problem in that I have an array that has been populated with strings ("item1", "item2", etc). However, at a certain point I need to pull one randomly out of the group, via a random number function. The issue is I cannot reference the items in the array by a number, I get an error. So when I try to get myArray(5) it doesn't work.
How can I work around this so I can grab a random item in my string array?
i see that theres the array.push and array.unshift, but thats just the beginning and the end of the array. how would i go about inserting an item(s) into an array at the desired index?
View 4 RepliesI have a label inside a repeater (rptInfos), and I have an arraycollection (Texts) that has the translations. The "Texts" content is changing when I change the language, and normally I use {Texts.getItemAt(219}} for example when I need a translated text. But in the repeater I have a translateable column, so I want to use it like this:
<s:Label text="{Texts.getItemAt(rptInfos.currentItem.DictID as int)}" />
but it says "Syntax error: expected a definition keyword (such as function) after attribute , not target".I wanted to translate it in the labels creationComplete event, but than I can forget about binding, so only when reloaded can I have the content to update.
I have this Array
Code:
var shoprubriken:Array = new Array();
shoprubriken[0] = "43";
shoprubriken[1] = "44";
[Code]....
Now I wanted to check on which Index Position maybe the 47 is
How can I archive this on a Button or Function?
I think it would be simplest to explain it like this:
[Code]...
<mx:itemRenderer>
<mx:Component>
<mx:Canvas>
[code]......
How to show the item index in my item renderer.Owner of the item renderer is TileList. [url],..
View 2 RepliesSo, for sending to individual streams we have to reference the connected netStream we want to send to in some way like this:
sendStream.peerStreams[0].send("MyFunction",param1,param2);
and I have to determine which peer I'm sending to by their ID such as "peerID1234"
I know that you can check the peerID of the stream by doing:
sendStream.peerStreams[0]["farID"]
how can I make my send stream function know to use the array index where the peerID is?
so basically it could be like:
sendStream.peerStreams[where peerStreams[]["farID"] == peerID].send("MyFunction",param1,param2);
I've got a subclass of AdvancedDataGrid showing a tree-like data structure. How can I, given the index returned by calculateDropIndex, get the item at that index? After reading through reams of code, it seems like the least terrible way is:
var oldSelectedIndex:int = this.selectedIndex;
var mouseOverIndex:int = this.calculateDropIndex(event);
this.selectedItem = mouseOverIndex;
var item:* = this.selectedItem;
this.selectedIndex = oldSelectedIndex;
The other option seems to be tinkering around with the iterator property... But, judging by the way I've seen it used, that will get pretty harry pretty quickly too. So, how can I get the item at a particular index in an advanced datagrid without going insane?
I'm doing a drag and drop operation on a tree using some help from Adobe's quick Starts:[URL]
The code suggested is roughly this:
var dropTarget:Tree = Tree(evt.currentTarget);
var i:int = dropTarget.calculateDropIndex(evt);
myTree.selectedIndex = i;
[Code].....
EDIT: I forgot to post that my current workaround is setting the selectedIndex = -1 after I get my node:XML. I'm afraid that if something bogs on the processor the user may see it select then deselect.
I've been trying yo convert Lee 3D carousel tut to AS3 and it pretty much there apart from one thing. I took Lee's as2 carousel 2 and applied what I know to convert it to AS3. I couldn't work out how to re-index each item properly. When the last item in the XML should appear under an item to it's left or right it does not due to numbers being rounded from the scaleX value being too close and causing the same number to be generated from more than one item therefore last item to be processed ending up on top. I've tried a few alternatives, but nothing has worked so far. Hopefully that makes to sense to someone.
If you download the files from Lee's tutorial http:[url].... open the fla, change the publish settings to Flash Player 9+ and AS3, remove all existing AS code, check the library item linkage as I've capitalized everything and add the following to the root timeline.The code causing the problem is this in the function mover:
Code: Select allvar index:int = Math.floor(mc.scaleX*10);
Code: Select allvar loader:URLLoader = new URLLoader();
loader.addEventListener(Event.COMPLETE, onLoaded);[code].............
I have a textBox and I am using it as a mail address input field where the user can type in several addresses, a bit same as in hotmail. Each address is rendered into a clickable button. Thus upon double-clicking on a specific address I want the item to be editable. After having edited the address when the user taps enter, the item is added to the list of mail adds.I am adding it using the code below:
flowBox.addChildAt( myItem, myindex);
However addChildAt seems to add the item as the last item in the list. But I want it to add the item the position where it was originally. Say the item was at position 2 in the mail list, after editing adn tapping enter, it should add at position 2 itself and not at the end of the list.
How can I find the index of a item dropped into a list in flex using a spark list?
View 2 RepliesI have a textBox and I am using it as a mail address input field where the user can type in several addresses, a bit same as in hotmail. Each address is rendered into a clickable button. Thus upon double-clicking on a specific address I want the item to be editable. After having edited the address when the user taps enter, the item is added to the list of mail adds.I am adding it using the code below:flowBox.addChildAt( myItem, myindex);However addChildAt seems to add the item as the last item in the list. But I want it to add the item the position where it was originally. Say the item was at position 2 in the mail list, after editing adn tapping enter,
View 2 RepliesI am trying to get the index of an item in a List object on a mouse roll over event (please keep in mind this is not the selectedIndex I need). Heres the code I am currently using:
list.addEventListener(ListEvent.ITEM_ROLL_OVER, onItemRollOver);
function onItemRollOver(e:Event):void {
var itemInfo:Number = 0;
/*This is where I need the Index Number of Item being Rolled over instead of Selected Item*/
itemInfo = list.selectedIndex;
txt_Display.text = 'Item Index #: ' + itemInfo;
play();
}
I change an item in Spark List. The item then moves to a different index in the list since I keep the List's dataProvider sorted. However, the selectedIndex stays where the item used to be. I want the List's selectedIndex to still be on the item that changed.
View 1 RepliesI have used a method to shuffle a part of a Array, but i noticed that it does not work very well.When i run this method I sometimes get empty array values.So if you would try the example below and test it out some times you would get a right result but sometimes a wrong result.For example when i run this i get in my trace output:
a,b,c,d,g,,e,f (here after the g it goes wrong)
a,b,c,f,g,d,e (here it goes right)
a,b,c,d,,g,f,e (here it goes wrong)[code]...
I have a datagrid with an xmlListCollection bound to it:
<mx:DataGrid id="dgCompetente" includeIn="Competente" x="10" y="66" width="547" height="468"
change="dgCompetente_changeHandler(event)" dataProvider="{colCompetente}"
editable="false">
[Code]......
I want the selectedIndex to remain the same. So, if I delete item 2, the next in the list should be selected. The problem is that if I delete item 2, item 3 will be selected and I have no idea why.
I put my mc's in an array.I have another array with strings.when the mc is clicked I want to get its position in the mc array and return the string from the same position in the string array.How do I do that?
PHP Code:
var numBtnArray:Array = new Array;
function addNumButtonsToStage():void{
[code].....
I know how to remove duplicates from an array, but what I'm trying to do is prevent an item from ever being added to an array in the first place if it already exists. I'm pulling in data from an xml feed in a loop, and I thought that searching for that values index would work, but no matter what, the index is always -1. Here's my code:
[Code]...
Maybe I'm misunderstanding the indexOf function, but I thought it was supposed to return -1 if a value did not exist in an array. What am I doing wrong?
I have this code to try to acess the values of the array in the arraycollection but it does not work it actually creates a value to the end of the arraycollection. can anyone tell me what im doing wrong i basically whant to modifys the individual arrays in the arraycollection and add Login_user.
Code:
for(var i:int = 0; i< dispArray.length; ++i){
dispArray.addItemAt({"login_user":"XXX"},i);
}
Is there a way to get the index of an array?
For instance, if I have an array:
buttons = Array("abc","def","ghi");
If I wanted to get the index dynamically of the string "ghi", could I do that with a certain function or piece of code?
I thought that there was a way to be able to name array indexes. Like instead of myArray[0], it could be myArray["tileFour"]. I thought that instead of using index numbers one could use index words.
View 1 RepliesIs there a way to get the index of an array?
For instance, if I have an array:
buttons = Array("abc","def","ghi");
If I wanted to get the index dynamically of the string "ghi", could I do that with a certain function or piece of code?
I have a game map made of tiles, each tile is stored in an array called _tiles.The very each tile has a "plantable" parameter, which determines whether or not something can be placed on it.Then i loop through the array and check the position of each its elements against the mosue cursor, so I know which tile am I hovering with my mouse.
And it works pretty good. The problem is that even though I know what is the position of the tile I'm having the cursor on, I still lack the knowledge of what index is that tile. I simply can't tell where exactly in the array is placed this tile. I just know its position. The reason why I want to know the index of it, is because it's the only way for me to set a proper flag, namely whether it's plantable or not. Here's the code:
ActionScript Code:
for(var j:int = 0; j < _tiles.length; j++)
{
[code]...
Is there a way I could specify the index of a array using this short code:[code]How would I go about giving a custom index name instead of it being myArray[0]? I could do it the long way like posted below, but I was wondering the there was a way to shorten this:[code]
View 2 Repliesi have an array of names that looks like this. var aNames:Array =new Array("jack","mike","Scott")
i have a text field called names which displays index 1 of the array.
and i have a button,when the button is pressed i want it to go to the next index of the array.
Is there a way I could specify the index of a array using this short code:
Code:
var myArray = new Array("teste");
How would I go about giving a custom index name instead of it being myArray[0]? I could do it the long way like posted below, but I was wondering the there was a way to shorten this:
Code:
var myArray = new Array();
myArray[myCustomIndex] = "testing";
Consider an array with x number of elements (of type Object) where some of the elements might be undefined.I use a for-each loop to access all the elements of the array that is not undefined (since it simply skips the undefined elements).But I also want the index of that particular element.The only option I can see is to use indexOf(). But it feels a bit like looking for water on the other side of the river so to speak.
When looping through long arrays each frame, is there a change indexOf() might slow it down? or does the for-each loop somehow know what index it's dealing with?