ActionScript 3.0 :: Check When Element In A Multi-dimensional Array Exists?
Jan 31, 2012
I'm using a multi-dimensional array (openImage[]) to track the open images in my multi-dimensional array (Images[]).
I would like to check and see if an element in a multi-dimensional array exists before I access it because there are rare occurrences where the data in openImage[] is not valid. I keep on getting errors every way I've tried it.[code]...
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Jun 13, 2011
I have a question regarding the use of mouse clicks events in a multi-dimensional array (or a "2D" array as we refer to them in Java and C++).
Background
I have an array of objects each with a corresponding mouse click event. Each object is stored at a location ranging from [0][0] to [5][8] (hence a 9 x 6 grid) and has the specific column and row number associated with it as well (i.e. tile [2][4] has a row number of 2 and a column number of 4, even though it is on the third row, fifth column). Upon each mouse click, the tile that is selected is stored in a temporary array. The array is cleared if a tile is clicked that does not share a column or row value equal to, minus or plus 1 with the currently targeted tile (i.e. clicking tile [1][1] will clear the array if there aren't any tiles stored that have the row/column number
[0][0], [0][1], [0][2],
[1][0], [1][1], [1][2],
[2][0], [2][1], [2][2]
or any contiguous column/row with another tile stored in the array, meaning that the newly clicked tile only needs to be sharing a border with one of the tiles in the temp array but not necessarily with the last tile stored).
Question
What is a clean, tidy way of programming this in AS3? Here are a couple portions of my code (although the mouse click event isn't finished/working correctly):
[Code]....
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Jan 8, 2010
I hope this isn't too vague, but I'm stuck on a problem that has put me in an Unfortunate Position. I'm Flash developer getting my feet wet with with AS3 and am trying to build an interior decoration tool for a client. My thinking so far has been: create the basic user interface, get the screen flow down, and then finally use a couple of simple arrays to store user selections and stuff like that.
Naturally my 'couple of simple arrays' is totally inadequate to model the many user decisions that my program has to take into account. So I find myself trying to create an enormous, multi-dimensional array with several layers of nesting and before Panic sets in. Here's an example of my thinking for the 'bedding' component of the application in pseudo ActionScript:
[Code]....
... keep in mind that this is just a fraction of what goes into bedding and there are several other of these kinds of arrays that would go into a room like flooring and walls and funture... all equally complex. And I'll need to frequently access different combinations like, how many options under bedding have no value associated and things like that.
So, I realize I'm out of my league and am going to get hurt on this,My questions are:
1) Could it be that using nested arrays like this actually isn't such a bad thing and I should just stick it out? That would suprise me, but I want to make sure I'm not already on the right path.
2) If not, where do I go from here if I want to do this right?
Off the top of my head I feel like I could maybe make everything class based. So my sheets are a class and beds have instances of sheets and rooms have instances of beds... etc. It think it would be complicated but might be the way to go. Or maybe, I go the XML route and store all of the room options in nested blank XML nodes that a user then populates as they move through the application. These are my thoughts but I'd like to hear what more experienced members of the community say.
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Jul 24, 2009
I have an 2D array that will look summat like this:
var numbers:Array=[[10,1,3],[9,2,4],[8,3,5],[7,4,6],[6,5,7],[5,6,8],[4,7,9],[3,8,10],[2,9,1],[1,10,2]];
now how do I order this array by the 3rd number so it looks like this:
2,9,1, 1,10,2, 10,1,3, 9,2,4 , 8,3,5, 7,4,6, 6,5,7, 5,6,8, 4,7,9, 3,8,10
I have tried:
trace(numbers.sortOn(0,Array.NUMERIC));
returns:
5,6,8, 9,2,4, 8,3,5, 7,4,6, 6,5,7, 10,1,3, 4,7,9, 3,8,10, 2, 9,1, 1,10,2
trace(numbers.sortOn(2,Array.NUMERIC));
returns:
5,6,8, 9,2,4, 8,3,5, 7,4,6, 6,5,7, 10,1,3, 4,7,9, 3,8,10, 2, 9,1, 1,10,2
trace(numbers.sortOn(3,Array.NUMERIC));
returns:
5,6,8, 9,2,4, 8,3,5, 7,4,6, 6,5,7, 10,1,3, 4,7,9, 3,8,10, 2, 9,1, 1,10,2
spaced out for ease of reading.
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