ActionScript 3.0 :: No Default Constructor Error Despite Call To Super()

Mar 15, 2010

I'm having a problem using superclass constructor with arguments. I've searched all over for the solution and found some really useful advice. Problem is i;ve followed it and it doesn't work... not for me anyway. So i've learned that you need to callthe super constructor in the subclass' constructor to avoid this error. problem is, this code still gets the same error....

[Code]...

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Actionscript 3 :: Calling Super() From Constructor With Varargs

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If a constructor takes its parameters as a vararg (...) it seems to be impossible to create a subclass that will just pass on that vararg to the superclass.

There is a related question with fix for this same situation for normal functions: Wrapping a Vararg Method in ActionScipt but I cannot get that to work with a super call.

base class:

public class Bla
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public function Bla(...rest)
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[Code]....

Aside from actually moving the handling of the parameters to the subclass or shifting it off to a separate initializer method

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ActionScript 2.0 :: Child Class Calls Super Constructor

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I got something just like that:

[code]...

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package
{
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The above does not work. It throws Error #2078: The name property of a Timeline-placed object cannot be modified. if the instance is assigned a name in the IDE, and it just doesn't work if no name is assigned in the IDE.

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Base Class

[code]...

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Following on from an answer I gave here: AS 3 | Cloning Png image data

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And if a transparent BitmapData is required, that too must be explicitly specified:

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So at no point can we rely on the shortest constructor form, without accepting a performance hit, and I can't understand why.Surely either the fillColor should default to black:

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[Code]....

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[Code]...

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There is no property with the name 'super'.

more specifically

Code:
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[code]...

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[code]....

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[Code].....

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I am going through the book gameprogramming university and checked to make sure my code matched.

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[Code].....

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[Code]....

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[Code].....

all works fine except when NextPrevPosition reaches the original value 0...and this is when I get the error message. It looks like the line "currentPort = new(POSITION[nextPrevPosition] as Class)(); is when it is happening.

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[Code].....

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