ActionScript 3.0 :: Return Four Random Numbers In Array?
Mar 2, 2011I'm trying to return four random number in an array. The total values of the four numbers has to be less that 200.
View 6 RepliesI'm trying to return four random number in an array. The total values of the four numbers has to be less that 200.
View 6 RepliesI have an assignment where I need to create an array with 9 numbers between 1 and 34, also none of the numbers need to appear twice.This is what I have so far, so as you can see I'm stuck on the part where I have to check if the number already exists in the array.[code]
View 5 RepliesWhat should I do so I end up with an array of random numbers like
[2, 6, 4, 9, 0, 3, 7, 8, 1, 5]
[3, 5, 8, 1, 9, 0, 6, 7, 2, 4]
I'm thinking like starting with an ordered array
[code]......
I am using actionscript 3 and I am creating an array of 16 buttons and need to use the function math.random to get it to pick 5 random unique numbers out of the array. As at the moment it is sometimes picking 5 unique numbers and sometimes it has duplicate buttons appearing?
View 1 RepliesThis seems quite easy, but I'm not that good with Flash, so it'd be really gr8 if anyone can help.I'm trying to create an array of random unique numbers from 0 to 39 so that I can list these numbers in a countdown and without repetition, ie: 25, 29, 11, 03, 17 etc.These are 40 different numbers, equal or greater than 0 and equal or less than 39.
View 7 RepliesLooking to generate random numbers b/w 0 and 19 with no duplicates to be put in Array.
View 6 RepliesI need to create an array with objects when using random numbers. This is the script I have:
ActionScript Code:
if(_root.EnemyCar.hitTest(_root.kill)){
_root.EnemyCar.removeMovieClip();
var lol6 = Math.floor(Math.random()*200);
if (lol6==2){_root.attachMovie("EnemyCar", "EnemyCar", _root.getNextHighestDepth(), {_x:74, _y:-100})};
if (lol6==1){_root.attachMovie("SwatVan1", "SwatVan1", _root.getNextHighestDepth(), {_x:114.9, _y:-45})};
if (lol6==0){_root.attachMovie("OilTanker", "OilTanker", _root.getNextHighestDepth(), {_x:74, _y:-250})};
}
As you can see the random number is from 0-250, I want to be able to have enemycar spawning from 2-20 and other movie clips spawning from 20-40 etc.
i am using actionscript 3, and the problem that I have is that i am creating an array of 16 buttons and need to use the function math.random to get it to pick 5 random unique numbers out of the array. as at the moment it is sometimes picking 5 unique numbers and sometimes it has duplicate buttons appearing?
View 3 RepliesHow do I make a random sequence of 10 numbers, from an array of 20 numbers in total, without repeating any of them on that sequence?
View 3 RepliesI have 10 movieclips on stage called mc1 mc2 etc ect and then I have one button which makes one of the mc's alpha = 0;The only thing is I would love the evenlistener add the number created by the array to be put after mc & "array number".So what the button should do is create one of the mc's visible whilst all others are not, and this should happen randomly without an mc showing up twice.
View 0 Repliesi'm attempting to populate an array with random numbers, but the random numbers must be a certain, minimum distance apart from each other.i've populated an array with 5 random numbers between 0 - 100:[code]after populating and sorting let's assume that myArray now contains these values:26, 27, 42, 92, 97 now i would like some ore all of the array values to be reset, if they need to be, so that they are at least a certain percentage (let's say 10%) of the maximum value (100) apart from each other.the first 2 values (26 and 27) are not at least 10% apart and neither are the last 2 values (92 and 97). however, if i simply moved the value 27 10% away from 26, so that 27 changes to 37, 37 now conflicts with the next value of 42.what is the best approach for populating an array of random numbers who's values will be at least a certain percentage apart from one another but still random.it may go without saying, but i'm looking for a solution that is portable, where maximum values and minimum distribution percentages can be anything, not just for my example above.
View 2 Replieshow to do this and not found much, so here goes:
I want to generate a variable number of random numbers less than 16 with no duplicate numbers
Ive posted the fla, and what i'm doing is generating a random number and putting it into an array then using a for loop to cycle through the array for each new random number to check if its already there. if it is, then i want to regenerate that number.
if you test the fla you'll see that all i get in my array is some lovely zero's and i sort of know why this is, but don't know how to stop it.
Generate four random numbers with the total of the four numbers equal to100?[code]...
View 8 Replieswhat is the syntax to pick how can i pick 6 random numbers from 49 numbers
View 9 RepliesI am generating random numbers between two numbers by the code bellow:
ActionScript Code:
public function randomRange(max:Number, min:Number = 0):Number
{
return Math.round(Math.random() * (1+max - min) + min);
}
trace(randomRange(3,-31));
But I need a code which will return some times '3' and some times '-31'. Not the number between them.
Making a random number between lets say 0 and 99 is relatively straight forward using the Math.random class What is the best way to create 100 unique random numbers from between 0 and 99 where no random number is repeated?Would I make a random number, chuck it into an array then the next random number created is checked against the array, and if the number has been created before try for another number?
View 2 RepliesI have been using Actionscript 3.0 in Adobe Flash Builder for a few weeks,and I really like it! Bare with me because I'm not really good at it, yet. Anyway, I was wondering how would I go by adding up odd numbers from an array of numbers? I know how to make all of the numbers add up, but adding only the odd numbers I'm not so sure how to do it.
View 5 RepliesThe Setup: For each movieclip the hittests a set of "target" movieclips an array is given a value. If mcIcon1 is dropped onto mcTarget1 the first number in the vacant array is given the value of one. The Issue: If I remove mcIcon1, for example, from the mcTarget1 movieclip I can't find a way of just removing the 1 from that array without the rest of the array numbers being reset.
[Code]...
How to get unique random numbers every time in AS3
I have searched but not able to get satisfactory results
How do I get random number between a range?Meaning: I want to pick a random number between 10 and 20, for example.Later, I may want a random number between 50 and 100, obviously excluding all numbers <50.
View 10 Repliesi'm just trying to do something really basic and I'm stumped.all i want to do is create a radom number onEnterFrameits to go at the end of a game i've made and the score will be radom at the end screenso far I have this below but it will not stop it just keeps going and going i've put stop(); in but that does not seem to work. I know its simple but I just can't see it.
this.onEnterFrame = function() {
display = Math.round (Math.random (10)*9)+1;
}
so what i understand from this im learning flash from [URL] tutorials and no matter how many times i listen to each word the guy says, i dont understand this part in the vid, we are making a die to roll from 1-6 although the code below is not the finali
[Code]...
I am creating a game for kids, which shows them how to tell the timeI need to put two random numbers into a textfield one for hours and one for minutesso that I can get the app to say show me 13:45 for examplehowever I do not want to include the time of 12:00 as this is where the clock will start and defeats the purposethe clock is 24 hour, going from 1-24 in hoursand 00-60 in minutesive looked everywhere on how to do this but cannot find an answerat the moment i have a textfield which displays the time as the user adds hours etc which i plan to hideso that i can say if this random number textfield is equal to the time textfield then display correct and so on
View 27 RepliesI'm generating a random number between min and max with this code:return min + (max - min) * Math.random();And it works. However, the random numbers are very little usually between "1 or 3" even if the max is 80.
View 3 RepliesI need to generate random numbers between 1 and 20 with a heavy emphasis on the one between 1 and 5, a light emphasis on 5-10, and a low emphasis on 10-20. I don't understand all the fancy probability words and all the stuff they say in the articles I've come across.
View 3 RepliesI have made a short script to generate some random numbers that must be unique. But it doesn't work as I thought it would have done! What is wrong in my code? Preciate some help to change my code so that generate unique random numbers.
[Code]...
Is there any way of preventing repeat numbers in random number generation?ve tried using the pop function and the delete function on elements in an array which are randomly selected, but cant get the effect I want. Ive even tried making two variable values equivalent to each other to try and constrict repetition
View 4 RepliesI'm traying to generate some random numbers: All numbers must be even and they cant be the same twice.Here is my code:
var number = new Array();
function numbers() {
var num = Math.ceil(Math.random()*10);
if ((num%2) != 0) {
[code]....
Basically what I need to do is I'm populating a library with a for loop with specific clips that need to be in a random order but never duplicates.So basically, it get selects a random number between 1-6 and if that number hasn't been selected yet, it will run it will use it as my integer in my for loop then continue running the loop until numbers 1-6 have all been used, but never used twice.
View 4 RepliesI have a custom slideshow that I've made that has a set of four images changing every 5 seconds. The images are randomly selected by a random number between 0 and the length of my XML.
how can I get four unique random numbers - i.e., getting 1, 4, 6, and 8 rather than 1, 4, 6, and 6?
So once a random number is selected, it can't be selected again.