ActionScript 3.0 :: Rotating A 3d Point Around A 3D Line?
Jul 2, 2011
Line is defined by two 3d points; (0,0,0) and (x,y,z). And there is also this 3d point. How can rotate this 3d point around the line?
Something like this (points indicate vectors in my expression, it's the same thing) :
I found some stuff on the internet but I couldn't really figure it out.
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Code:
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I have been looking at how to reflect a point in a line, and found this question which seems to do the trick, giving this formula to calculate the reflected point:
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Is there a simple way to calculate (x', y'), the reflection of point (x, y) in a line, where the line is described by the two points (x1, y1) and (x2, y2)?
Edit:
I've found a formula which does this, but it seems as though it does not work with lines that look like they have equation y = x.
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public static function reflect(p:Point, l:Line):Point
{
// (l.sx, l.sy) = start of line
[Code]....
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Code:
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To make this easy, lets say I have a movie clip with a diagonal line in it (top left to bottom right).
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5, 10
or
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How could I find the distance between a given point and a drawn line? I was thinking about using the point-slope formula to draw a perpendicular line between the point and the line and measuring it as the distance, but I'm not quite sure how to do this in as3.
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