Jquery :: Layer Pictures On Top Of Each Other On A Webpage?
Jun 27, 2011
I want to build a website that is a "dress up" game where you can click on different accessories and they will layer on top of each other. Because it's a little difficult to describe, I found these examples which should hopefully highlight what I am trying to do: This is the closest website that I have found, but I can't seem to find the code that is figuring out how the images should lay on top of each other. Similar to this iOS princess game
I have hundreds of different accessories as images right now, and (similar to the game above) I need to support being able to choose more than one. So I need a solution that doesn't require me to pre-save an image of every permeation of accessory combinations on top of the princess (as that would be millions of predefined images). Ideally I would like a Javascript/jQuery or CSS solution but will take that people have. Flash suggestions would be ful as well.
So my questions are: How is the example website above lining up all of the images on top of each other? I can't seem to find any CSS or Javascript code that is doing it? Are there how to build this type of website (links, tutorials or code examples would be great)?
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[code].....
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this.createEmptyMovieClip("pos", total);
pos.moveTo(radius.b, 0);
pos.beginGradientFill("radial", [0xCCCCCC, 0x999999], [100, 100], [0, 255], {matrixType:"box", x:-radius.b-radius.b/2, y:-radius.b-radius.b/2, w:radius.b*2, h:radius.b*2, r:0});
for (var radians = 0; radians
I get a error for the last line. The error is this:
**Error** Scene=Scene 1, layer=Layer 1, frame=1:Line 11: ';' expected
for (var radians = 0; radians
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