how to get to the "TEXTUAL" node and its children?
Code:
myXML..menuItem.(@name == "TEXTUAL").children()[i].@name
because if there were more than one attribute with the same name this would fail like a plain out of the sky
Code:
<menuItem name="HOME" >
<menuItem name="MEMBERS"></menuItem>
<menuItem name="IDEAS"></menuItem>[code].....
how to get to the "TEXTUAL" node and its children?
but dont suggest me attribute searching on any node:
Code: myXML..menuItem.(@name == "TEXTUAL").children()[i].@name
because if there were more than one attribute with the same name this would fail like a plain out of the sky
Code:
<menuItem name="HOME" >
<menuItem name="MEMBERS"></menuItem>
<menuItem name="IDEAS"></menuItem>
[Code]....
I want to basically copy an xml object I have created, take the children from a specified node and make a new xml object from them and put this new xml into the tree component. Can you see what is wrong with this?
[Code]...
I have xml files with many children and then further more children.
like
<level1>
<child id=1 > <nodes....> </child1>
<child id=2 > <nodes....> </child1>
<child id=3 > <nodes....> </child1>
<child id=4 > <nodes....> </child1>
</level1>
Is it possible to get the children nodes of child with id = 1 in AS3
I have a parent node and I'm trying to get each child node under that parent and store it into an arraycollection? How could I go by doing this?
View 1 RepliesIf i want check parent node checkbox means below childerns checkbox will select automatic .[code]...
View 2 RepliesI would like to do a simple check when I load an XML file for the most number of characters of children nodes. In other words, if any child node contains more than 50 characters I want to to configure stage objects differently.[code]
View 2 RepliesI've developed a CMS system that allows users to change the textual content and save the changes back to an XML doc.All works fine in English but the writing to the XML Keeps falling over when it reaches a foreign character.. Even when wrapped with the CDDATA tag.The application needs to support users translating the content into different languages.
I'm using zinc to write out the XML string.During runtime all changes are stored back directly to the XML object ( the same one that is loaded at the start and is used to populated the CMS) then I use XML.toString() to create a string variable to pass to zinc to save out the file..
I'm making a OSX-finder-type file browser in CS4.The Structure for the folder and files is being generated by a PHP in a XML, heres an example:(sorry the xml is not sorted, but the command i'm using in php doesn't sort it)
Code:
<root>
<dir name="images">
[code]....
I have an AdvancedDataGrid tree with a ArrayCollection as its dataprovider. Now, for instance, i drag a leaf from one node to another node. To catch the event I'm adding a Listener to dragComplete.
[Code]...
My Problem: I want to know the new node where the leaf was dropped. Actually i would have expected that in the event there is a property like dropParent. This is not the case.
I have a tree im my mxml that uses a XMLListCollection as dataProvider. Itīs XML is like:
<list>
<conta nome="Plano de Contas" id="1">
<conta nome="Creditos" id="2" />
<conta nome="Vendas" id="4" />
[code]....
How can I make the node for, say, id==4 visible AND selected?
i have a question whether we can create a new xml node in as3 node containing dynamic value inside.....
as like if i want to get like..var newNode:XML = <IMAGE FULL="fullimages/3.jpg"THUMB="thumbnails/3.jpg"/>
where the images are dynamic values...
I thought this was going to be easy! I would like to search an XML file for a particular data set i.e. set of nodes depending on a passed variable. However, storing a subset of my XML file via Code:var gallery = this.firstChild; and then searching 'gallery' as you would an array-using a for()-doesn't work since this.firstChild isn't returning an array
Code:
<gallery>
<collection title="Christmas 2004">
[code].....
I've got some xml:
var xmlData:XML =
<1stNode>
<buttonID>first child node value</buttonID>
[Code]....
Then I want to read specific node value based on a value passed to a function. .
var buttonID = new Button;
var imageID = new Image;
var labelID = new Label;
[Code]....
I'm don't know how to get the value when node name is dynamically changed.
just trying to get straight how this works. Say I create some XML like so:
ActionScript Code:
var sample:XML = <sample>
<items>
[code]......
In this game attached I need the old Children (rats) to hurt the character when he walks into them, however only the most recently added Child is active in that way... also the rats seem to appear above the character instead of below, is there any way to resolve these issues??
View 4 RepliesI have a Sprite called pageContent. Inside pageContent are 12 more Sprites with unique names, a couple of Buttons, and some TextFields. Inside each of the 12 Sprites I have either one or two TextFields and one TextInput. My question is, since they are children inside a child of pageContent, how can I access them? Here is how I am trying to do it:
[Code]...
In my mind, this should totally work. But surprise, surprise, it doesn't. I have debugged it and it works fine for the first two lines, but when it tries to get numChildren of a Child of pageContent (line 3), I get this error: PHP Code: 1119: Access of possibly undefined property numChildren through a reference with static type flash.display:DisplayObject.
I want to have a rollover effect of a movieclip (mo1) inside a movieclip (mo) of another movieclip (popup1).Is it possible to do that? I try calling it using this code in the frame 1 of my flash, am i doing wrongly?
Code:
popup1.mo.mo1.onRollOver = function() {
popup1.mo.mo1.gotoAndStop(2);
[code]......
Newbie to XML here and I have what I *hope* is an easy problem, but I just don't know the answer. And as I have to try and show this by Monday, I'm sort of stuck. I am trying to pull in information about houses via an xml file. Each house has 1 address, 1 owner, 1 description, and about 6 photos. I have no problem accessing the address, owner, etc, and I can always access the first photo, but whenever I cycle through the photos, I seem to cycle through the first photo for every house, not every photo for each house.
Basically, I need the children <images> to go up by one, without the the parent going up by 1. I am hoping I am describing this well. My code looks like this:
[Code]...
I have a Canvas which has many components inside it and those again, have many components inside them.
getChildren() returns only the top level children. What is the best way to retrieve all the children (children of children of children and so on).
Well, I sorta know how to do this by iterating through the children, but the code is really messy. I'd prefer to use a nice recursive function. Has anyone written this before? Or is there a Util class to do this?
I am trying to pull in information about houses via an xmlfile. Each house has 1 address, 1 owner, 1 description, and about 6photos. I have no problem accessing the address, owner, etc, and Ican always access the first photo, but whenever I cycle through thephotos, I seem to cycle through the first photo for every house,not every photo for each house.Basically, I need the children <images> to go up byone, without the the parent going up by 1. I am hoping I amdescribing this well.My code looks like this:
total = xmlNode.childNodes.length;
totalb =
xmlNode.childNodes[0].childNodes[5].childNodes.length;
[code].....
I have an ArrayCollection that is read to generate containers in an accordion programmatically:
<s:ArrayCollection id="_ac_ps">
<fx:Object label="Block and lot" data="_blocklot" searchType="districtblocklot"
info="" />
[code].......
for some reason STORAGE[0].getChildAt(0) works whereas liner.getChildAt(0).getChildAt(0) does not. STORAGE is a movieclip and a child of liner. the error is something about not being able to use getChildAt on a display object. what's wrong? is there any other approach i could use? PS: liner.getChildAt(0) works and does indeed seem to refer to STORAGE[0]
View 2 RepliesI have a datagrid called dg that has data populated to it thru an external XML. What I am trying to achieve is whenever someone clicks on an item in the grid it stores that items coordinates to a variable called locCoordinates. At this moment it is tracing out the coordinates for all of the items in the grid. I just dont know how to go about only getting the selected items coordinates.
XML Snippet
Code:
<?xml version="1.0" encoding="UTF-8"?>
<Document>
<Placemark>
[code]....
Given
<nodeList>
<crazyNode>Data to be overwrited</crazyNode>
<simpleNode>Normal data</simpleNode>
<crazyNode>Actual data</crazyNode>[code]......
I want to get the last crazyNode (the one which contains Actual data).I know how to access the first node, for example:
nodeList.crazyNode[0]
And I guess a solution would be
nodeList.crazyNode[nodeList.crazyNode.length() - 1]
But for some reason I don't like doing that, too verbose and maybe there's a method more elegant.
This might be a stupid question:
Let's say I have:
var myXML:XML = new XML(<node></node>);
and I want to set a value for the <node>, so that the xml would become[code]...
I want to add new node to the current XML file. It already contain some data and I want to add new node with Flash. I know how to retrieve the data but don't know how to insert
View 3 RepliesDoes anyone know of a way to get an XML node's name? Or to call the node without knowing it's name? I'm looking for something generic and reusable, with the child-node name not hard coded. My XML looks like this:
Code:
<list>
<doc>145</doc>
<doc>388</doc>[code]....
I've tried to import a string into the class to replace "doc", using XMLList, descendants, elements, children, etc. and nothing seems to work short of turning the whole thing into a string and chopping it up later.
I currently have the following XML code:
[Code]...
That however didn't trace anything. how I can read the galleryname?
How would I move an XML node? For instance:
<root>
<child />
<child />
<child />
<child />
<child />
</root>
I want to move the third <child> node up one.