ActionScript 3.0 :: Increase & Decrease Operators - Count The Number Of Correct And Incorrect Answers
Jul 11, 2009
I'm using AS3 in timeline. I'm working on a multiplication game. The idea is to count the number of correct and incorrect answers and give the user a final count. I have several dynamic text boxes: box1 and box2 will multiply each other.box3 = input box; user inputs answerbox4 = message displaysbox5 = correct1; displays correct countbox6 = correct2; displays incorrect count buttonsbt_1 = checks answersbt_2 = resets problems PROBLEM:I CAN'T GET BOX6 COUNT THE INCORRECT ANSWERS. HOW CAN I FIX THIS PROBLEM?
[Code]...
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return i;
[Code].....
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I have a Dynamic Text area called txt, I write the value 5000 by txt.text="5000"; In my scene there will be 2 buttons. When one of the buttons is pushed the value will decrease 250 by 250. For example; at first push it will decrease to 4750, at the second push it will decrease to 4500 and so on...And when it is pushed to the other button this value will increase 250 by 250.For example; the value will be:4500 by pushing twice to the decreasing button, then it'll be:4750 by pushing once to the increasing button.I tried with the below codes but it didn't work. The value decreases only once, it doesn't keep on decreasing when I pushed twice to the decreasing button.The value seems as 5000250.
[Code]...
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Jan 18, 2011
I have a Dynamic Text area called txt, I write the value 5000 by txt.text="5000";
In my scene there will be 2 buttons. When one of the buttons is pushed the value will decrease 250 by 250. For example; at first push it will decrease to 4750, at the second push it will decrease to 4500 and so on...And when it is pushed to the other button this value will increase 250 by 250. For example; the value will be:4500 by pushing twice to the decreasing button, then it'll be:4750 by pushing once to the increasing button. I tried with the below codes but it didn't work. The value decreases only once, it doesn't keep on decreasing when I pushed twice to the decreasing button.The value seems as 5000250.
txt1 = txt.text;
Decrease.onRelease = function() {
txt.text = txt1 - "250";
};
Increase.onRelease = function() {
txt.text = txt1 + "250";
};
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on(release)
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Files attached here [URL]
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[Code]...
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[Code]...
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explain this...
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trace(i);
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ActionScript Code:
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Quote:
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Code:
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[code]....
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