ActionScript 3.0 :: Reposition Object Depending On How Many Left

Oct 24, 2011

I have a game: The object circled is the amount of shots you have left. But it removes the last object in the array, so the last bullet, its hard to explain, I have 20 bullets, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15, 16, 17, 18, 19, 20. The array is removing the 1 first. Well what I am saying is number 1 is actually number 20, so the array is doing nothing wrong, I did. But I am not sure how to reverse the order.

So [ its removing this one-> o o o o o o o o o o o o o o o o o o o]
But [ --------------------------------- o o o o o o o o o o o o o o o o o o o <- I want it to remove this one]

The reason being is because the user cannot see how many they have left, so think angry birds, the amount of birds is displayed according to the amount there allowed, its to the left of the slingshot, like mine, every time the bird is shot, the rest of the birds shimmey towards the slingshot untill there is none left --- This is what I want, but have managed to confuse myself aswell as you most likely.

Here is my code, to generate and take awau my bullets/birds
public function createShotIcons() {
shotIcons = new Array();
for(var i:uint=0;i<20;i++) {
var newShot:ShotIcon = new ShotIcon();
newShot.x = 200-i*15;
newShot.y = 300;
addChild(newShot);
shotIcons.push(newShot);
}} public function removeShotIcon() {
removeChild(shotIcons.pop());
}

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